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Fix shared_ptr::owner_before (#1274)

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This method is supposed to give equivalence iff two shared pointers both
own the same object, even if they point to different addresses. We can't
control the exact order of the control blocks in memory, so the test can
only check that this equivalence/non-equivalence relationship holds, and
this is in fact all that it should check.
This commit is contained in:
Steven Dee (Jōshin) 2024-09-01 17:34:39 -04:00 • committed by GitHub
parent 48b703b3f6
commit ae57fa2c4e
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2 changed files with 8 additions and 11 deletions
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8
ctl/shared_ptr.h
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@ -335,11 +335,10 @@ class shared_ptr
return p;
}
#if 0 // TODO(mrdomino): find a different way
template<typename U>
bool owner_before(const shared_ptr<U>& r) const noexcept
{
return p < r.p;
return rc < r.rc;
}
template<typename U>
@ -347,7 +346,6 @@ class shared_ptr
{
return !r.owner_before(*this);
}
#endif
private:
template<typename U>
@ -422,13 +420,13 @@ class weak_ptr
template<typename U>
bool owner_before(const weak_ptr<U>& r) const noexcept
{
return p < r.p;
return rc < r.rc;
}
template<typename U>
bool owner_before(const shared_ptr<U>& r) const noexcept
{
return p < r.p;
return rc < r.rc;
}
private: