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Improve wait statuses
This change has the insight that dwExitCode isn't an exit code but rather should be used to pass the wait status. This lets us report killing as a termination status, similar to UNIX. This change also fixes the fact that exit(259) on Windows will break the parent due way WIN32 is designed. We now work around that. It turns out that NetBSD and OpenBSD, will let you have exit codes beyond 255. This change will let you use them when it's possible.
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22 changed files with 259 additions and 75 deletions
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@ -1,5 +1,5 @@
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/*-*- mode:c;indent-tabs-mode:nil;c-basic-offset:2;tab-width:8;coding:utf-8 -*-│
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│vi: set net ft=c ts=2 sts=2 sw=2 fenc=utf-8 :vi│
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/*-*- mode:c;indent-tabs-mode:t;c-basic-offset:8;tab-width:8;coding:utf-8 -*-│
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│vi: set et ft=c ts=8 tw=8 fenc=utf-8 :vi│
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╚──────────────────────────────────────────────────────────────────────────────╝
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│ │
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│ Musl Libc │
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@ -31,41 +31,38 @@ asm(".ident\t\"\\n\\n\
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Musl libc (MIT License)\\n\
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Copyright 2005-2014 Rich Felker, et. al.\"");
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asm(".include \"libc/disclaimer.inc\"");
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// clang-format off
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/**
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* Compares two version strings.
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*/
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int strverscmp(const char *l0, const char *r0) {
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const unsigned char *l = (const void *)l0;
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const unsigned char *r = (const void *)r0;
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size_t i, dp, j;
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int z = 1;
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/* Find maximal matching prefix and track its maximal digit
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* suffix and whether those digits are all zeros. */
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for (dp = i = 0; l[i] == r[i]; i++) {
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int c = l[i];
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if (!c) return 0;
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if (!isdigit(c)) {
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dp = i + 1, z = 1;
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} else if (c != '0') {
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z = 0;
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}
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}
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if (l[dp] != '0' && r[dp] != '0') {
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/* If we're not looking at a digit sequence that began
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* with a zero, longest digit string is greater. */
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for (j = i; isdigit(l[j]); j++) {
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if (!isdigit(r[j])) {
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return 1;
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}
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}
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if (isdigit(r[j])) {
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return -1;
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}
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} else if (z && dp < i && (isdigit(l[i]) || isdigit(r[i]))) {
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/* Otherwise, if common prefix of digit sequence is
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* all zeros, digits order less than non-digits. */
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return (unsigned char)(l[i] - '0') - (unsigned char)(r[i] - '0');
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}
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return l[i] - r[i];
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int strverscmp(const char *l0, const char *r0)
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{
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const unsigned char *l = (const void *)l0;
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const unsigned char *r = (const void *)r0;
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size_t i, dp, j;
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int z = 1;
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/* Find maximal matching prefix and track its maximal digit
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* suffix and whether those digits are all zeros. */
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for (dp=i=0; l[i]==r[i]; i++) {
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int c = l[i];
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if (!c) return 0;
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if (!isdigit(c)) dp=i+1, z=1;
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else if (c!='0') z=0;
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}
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if (l[dp]-'1'<9U && r[dp]-'1'<9U) {
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/* If we're looking at non-degenerate digit sequences starting
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* with nonzero digits, longest digit string is greater. */
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for (j=i; isdigit(l[j]); j++)
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if (!isdigit(r[j])) return 1;
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if (isdigit(r[j])) return -1;
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} else if (z && dp<i && (isdigit(l[i]) || isdigit(r[i]))) {
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/* Otherwise, if common prefix of digit sequence is
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* all zeros, digits order less than non-digits. */
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return (unsigned char)(l[i]-'0') - (unsigned char)(r[i]-'0');
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}
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return l[i] - r[i];
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}
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