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lib: assume char is unsigned 

Now that we use -funsigned-char, there's no need for this kind of ifdef.

Signed-off-by: Jason A. Donenfeld <Jason@zx2c4.com>
This commit is contained in:
Jason A. Donenfeld 2022-11-03 01:50:05 +01:00
parent 3bc753c06d
commit 0445d1bae1
2 changed files with 0 additions and 16 deletions
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4
lib/is_signed_type_kunit.c
View File

@ -21,11 +21,7 @@ static void is_signed_type_test(struct kunit *test)
KUNIT_EXPECT_EQ(test, is_signed_type(bool), false);
KUNIT_EXPECT_EQ(test, is_signed_type(signed char), true);
KUNIT_EXPECT_EQ(test, is_signed_type(unsigned char), false);
#ifdef __CHAR_UNSIGNED__
KUNIT_EXPECT_EQ(test, is_signed_type(char), false);
#else
KUNIT_EXPECT_EQ(test, is_signed_type(char), true);
#endif
KUNIT_EXPECT_EQ(test, is_signed_type(int), true);
KUNIT_EXPECT_EQ(test, is_signed_type(unsigned int), false);
KUNIT_EXPECT_EQ(test, is_signed_type(long), true);

12
lib/test_printf.c
View File

@ -179,18 +179,6 @@ test_number(void)
* behaviour.
*/
test("00|0|0|0|0", "%.2d|%.1d|%.0d|%.*d|%1.0d", 0, 0, 0, 0, 0, 0);
#ifndef __CHAR_UNSIGNED__
{
/*
* Passing a 'char' to a %02x specifier doesn't do
* what was presumably the intention when char is
* signed and the value is negative. One must either &
* with 0xff or cast to u8.
*/
char val = -16;
test("0xfffffff0|0xf0|0xf0", "%#02x|%#02x|%#02x", val, val & 0xff, (u8)val);
}
#endif
}
static void __init