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wimax/i2400m: use struct_size() helper
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; size = sizeof(struct foo) + count * sizeof(void *); instance = alloc(size, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: size = struct_size(instance, entry, count); This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavo@embeddedor.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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1 changed files with 2 additions and 2 deletions
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@ -1260,8 +1260,8 @@ int i2400m_rx(struct i2400m *i2400m, struct sk_buff *skb)
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goto error_msg_hdr_check;
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result = -EIO;
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num_pls = le16_to_cpu(msg_hdr->num_pls);
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pl_itr = sizeof(*msg_hdr) + /* Check payload descriptor(s) */
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num_pls * sizeof(msg_hdr->pld[0]);
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/* Check payload descriptor(s) */
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pl_itr = struct_size(msg_hdr, pld, num_pls);
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pl_itr = ALIGN(pl_itr, I2400M_PL_ALIGN);
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if (pl_itr > skb_len) { /* got all the payload descriptors? */
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dev_err(dev, "RX: HW BUG? message too short (%u bytes) for "
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