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net/rose: Fix to not accept on connected socket 

If you call listen() and accept() on an already connect()ed
rose socket, accept() can successfully connect.
This is because when the peer socket sends data to sendmsg,
the skb with its own sk stored in the connected socket's
sk->sk_receive_queue is connected, and rose_accept() dequeues
the skb waiting in the sk->sk_receive_queue.

This creates a child socket with the sk of the parent
rose socket, which can cause confusion.

Fix rose_listen() to return -EINVAL if the socket has
already been successfully connected, and add lock_sock
to prevent this issue.

Signed-off-by: Hyunwoo Kim <v4bel@theori.io>
Reviewed-by: Kuniyuki Iwashima <kuniyu@amazon.com>
Link: https://lore.kernel.org/r/20230125105944.GA133314@ubuntu
Signed-off-by: Jakub Kicinski <kuba@kernel.org>
This commit is contained in:
Hyunwoo Kim 2023-01-25 02:59:44 -08:00 committed by Jakub Kicinski
parent ffffd2454a
commit 14caefcf98
1 changed files with 8 additions and 0 deletions
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8
net/rose/af_rose.c
View File

@ -488,6 +488,12 @@ static int rose_listen(struct socket *sock, int backlog)
{
struct sock *sk = sock->sk;
lock_sock(sk);
if (sock->state != SS_UNCONNECTED) {
release_sock(sk);
return -EINVAL;
}
if (sk->sk_state != TCP_LISTEN) {
struct rose_sock *rose = rose_sk(sk);
@ -497,8 +503,10 @@ static int rose_listen(struct socket *sock, int backlog)
memset(rose->dest_digis, 0, AX25_ADDR_LEN * ROSE_MAX_DIGIS);
sk->sk_max_ack_backlog = backlog;
sk->sk_state = TCP_LISTEN;
release_sock(sk);
return 0;
}
release_sock(sk);
return -EOPNOTSUPP;
}