amd64_edac: fix DRAM base and limit extraction

On Fam10h and above, F1x[1, 0][7C:40] are DRAM Base/Limit registers
which specify the destination node of a DRAM address. Those address
boundaries are being extracted into ->dram_base[] and ->dram_limit[].
Correct the extraction masks to match the respective address bits.

Signed-off-by: Borislav Petkov <borislav.petkov@amd.com>
This commit is contained in:
Borislav Petkov 2009-09-22 16:48:37 +02:00
parent 9d858bb10a
commit 66216a7a15

View file

@ -1368,8 +1368,8 @@ static void f10_read_dram_base_limit(struct amd64_pvt *pvt, int dram)
pvt->dram_IntlvEn[dram] = (low_base >> 8) & 0x7;
pvt->dram_base[dram] = (((((u64) high_base & 0x000000FF) << 32) |
((u64) low_base & 0xFFFF0000))) << 8;
pvt->dram_base[dram] = (((u64)high_base & 0x000000FF) << 40) |
(((u64)low_base & 0xFFFF0000) << 24);
low_offset = K8_DRAM_LIMIT_LOW + (dram << 3);
high_offset = F10_DRAM_LIMIT_HIGH + (dram << 3);
@ -1390,9 +1390,9 @@ static void f10_read_dram_base_limit(struct amd64_pvt *pvt, int dram)
* Extract address values and form a LIMIT address. Limit is the HIGHEST
* memory location of the region, so low 24 bits need to be all ones.
*/
low_limit |= 0x0000FFFF;
pvt->dram_limit[dram] =
((((u64) high_limit << 32) + (u64) low_limit) << 8) | (0xFF);
pvt->dram_limit[dram] = (((u64)high_limit & 0x000000FF) << 40) |
(((u64) low_limit & 0xFFFF0000) << 24) |
0x00FFFFFF;
}
static void f10_read_dram_ctl_register(struct amd64_pvt *pvt)