[IA64] Extract correct break number for break.b

break.b does not store the break number in cr.iim, instead it stores 0,
which makes all break.b instructions look like BUG().  Extract the
break number from the instruction itself.

Signed-off-by: Keith Owens <kaos@sgi.com>
Signed-off-by: Tony Luck <tony.luck@intel.com>
This commit is contained in:
Keith Owens 2005-05-27 23:09:00 -07:00 committed by Tony Luck
parent 86ebacd360
commit 70aa488cff
1 changed files with 18 additions and 0 deletions

View File

@ -111,6 +111,24 @@ ia64_bad_break (unsigned long break_num, struct pt_regs *regs)
siginfo_t siginfo;
int sig, code;
/* break.b always sets cr.iim to 0, which causes problems for
* debuggers. Get the real break number from the original instruction,
* but only for kernel code. User space break.b is left alone, to
* preserve the existing behaviour. All break codings have the same
* format, so there is no need to check the slot type.
*/
if (break_num == 0 && !user_mode(regs)) {
struct ia64_psr *ipsr = ia64_psr(regs);
unsigned long *bundle = (unsigned long *)regs->cr_iip;
unsigned long slot;
switch (ipsr->ri) {
case 0: slot = (bundle[0] >> 5); break;
case 1: slot = (bundle[0] >> 46) | (bundle[1] << 18); break;
default: slot = (bundle[1] >> 23); break;
}
break_num = ((slot >> 36 & 1) << 20) | (slot >> 6 & 0xfffff);
}
/* SIGILL, SIGFPE, SIGSEGV, and SIGBUS want these field initialized: */
siginfo.si_addr = (void __user *) (regs->cr_iip + ia64_psr(regs)->ri);
siginfo.si_imm = break_num;