i915: make inject_virtual_interrupt() void

The single caller of inject_virtual_interrupt() ignores the return value
anyway. This allows us to simplify eventfd_signal() in follow-up
patches.

Link: https://lore.kernel.org/r/20231122-vfs-eventfd-signal-v2-1-bd549b14ce0c@kernel.org
Reviewed-by: Jan Kara <jack@suse.cz>
Reviewed-by: Zhenyu Wang <zhenyuw@linux.intel.com>
Reviewed-by: Jens Axboe <axboe@kernel.dk>
Signed-off-by: Christian Brauner <brauner@kernel.org>
This commit is contained in:
Christian Brauner 2023-11-22 13:48:22 +01:00
parent 600f111ef5
commit 8588487192
1 changed files with 6 additions and 7 deletions

View File

@ -422,7 +422,7 @@ static void init_irq_map(struct intel_gvt_irq *irq)
#define MSI_CAP_DATA(offset) (offset + 8)
#define MSI_CAP_EN 0x1
static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
static void inject_virtual_interrupt(struct intel_vgpu *vgpu)
{
unsigned long offset = vgpu->gvt->device_info.msi_cap_offset;
u16 control, data;
@ -434,10 +434,10 @@ static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
/* Do not generate MSI if MSIEN is disabled */
if (!(control & MSI_CAP_EN))
return 0;
return;
if (WARN(control & GENMASK(15, 1), "only support one MSI format\n"))
return -EINVAL;
return;
trace_inject_msi(vgpu->id, addr, data);
@ -451,10 +451,9 @@ static int inject_virtual_interrupt(struct intel_vgpu *vgpu)
* returned and don't inject interrupt into guest.
*/
if (!test_bit(INTEL_VGPU_STATUS_ATTACHED, vgpu->status))
return -ESRCH;
if (vgpu->msi_trigger && eventfd_signal(vgpu->msi_trigger, 1) != 1)
return -EFAULT;
return 0;
return;
if (vgpu->msi_trigger)
eventfd_signal(vgpu->msi_trigger, 1);
}
static void propagate_event(struct intel_gvt_irq *irq,