compiler-types.h: Include naked type in __pick_integer_type() match

__pick_integer_type() checks whether the type of its first argument is
compatible with an explicitly signed or unsigned integer type, returning
the compatible type if it exists.

Unfortunately, 'char' is neither compatible with 'signed char' nor
'unsigned char', so add a check against the naked type to allow the
__unqual_scalar_typeof() macro to strip qualifiers from char types
without an explicit signedness.

Reported-by: Rasmus Villemoes <linux@rasmusvillemoes.dk>
Signed-off-by: Will Deacon <will@kernel.org>
This commit is contained in:
Will Deacon 2020-06-05 11:05:51 +01:00
parent 5872f1a2e5
commit 8d4beed7bb
1 changed files with 7 additions and 2 deletions

View File

@ -220,9 +220,14 @@ struct ftrace_likely_data {
#define __pick_scalar_type(x, type, otherwise) \
__builtin_choose_expr(__same_type(x, type), (type)0, otherwise)
/*
* 'char' is not type-compatible with either 'signed char' or 'unsigned char',
* so we include the naked type here as well as the signed/unsigned variants.
*/
#define __pick_integer_type(x, type, otherwise) \
__pick_scalar_type(x, unsigned type, \
__pick_scalar_type(x, signed type, otherwise))
__pick_scalar_type(x, type, \
__pick_scalar_type(x, unsigned type, \
__pick_scalar_type(x, signed type, otherwise)))
#define __unqual_scalar_typeof(x) typeof( \
__pick_integer_type(x, char, \