ti: Remove extern from function prototypes

There are a mix of function prototypes with and without extern
in the kernel sources.  Standardize on not using extern for
function prototypes.

Function prototypes don't need to be written with extern.
extern is assumed by the compiler.  Its use is as unnecessary as
using auto to declare automatic/local variables in a block.

Signed-off-by: Joe Perches <joe@perches.com>
This commit is contained in:
Joe Perches 2013-09-23 11:37:59 -07:00
parent d6cc64ef73
commit 95f7f1519d

View file

@ -127,8 +127,8 @@ struct cpts {
};
#ifdef CONFIG_TI_CPTS
extern void cpts_rx_timestamp(struct cpts *cpts, struct sk_buff *skb);
extern void cpts_tx_timestamp(struct cpts *cpts, struct sk_buff *skb);
void cpts_rx_timestamp(struct cpts *cpts, struct sk_buff *skb);
void cpts_tx_timestamp(struct cpts *cpts, struct sk_buff *skb);
#else
static inline void cpts_rx_timestamp(struct cpts *cpts, struct sk_buff *skb)
{
@ -138,8 +138,7 @@ static inline void cpts_tx_timestamp(struct cpts *cpts, struct sk_buff *skb)
}
#endif
extern int cpts_register(struct device *dev, struct cpts *cpts,
u32 mult, u32 shift);
extern void cpts_unregister(struct cpts *cpts);
int cpts_register(struct device *dev, struct cpts *cpts, u32 mult, u32 shift);
void cpts_unregister(struct cpts *cpts);
#endif