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pinctrl: intel: Protect set wake flow by spin lock

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It seems intel_gpio_irq_wake() misses lock protection against I/O flow.
Use spin lock here as well.

Signed-off-by: Andy Shevchenko <andriy.shevchenko@linux.intel.com>
Acked-by: Mika Westerberg <mika.westerberg@linux.intel.com>
Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
This commit is contained in:
Andy Shevchenko 2016-07-08 14:30:46 +03:00 committed by Linus Walleij
parent a6e5e4a624
commit 9a520fd99f
1 changed files with 5 additions and 0 deletions
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5
drivers/pinctrl/intel/pinctrl-intel.c
View file

@ -796,12 +796,15 @@ static int intel_gpio_irq_wake(struct irq_data *d, unsigned int on)
const struct intel_community *community;
unsigned pin = irqd_to_hwirq(d);
unsigned padno, gpp, gpp_offset;
unsigned long flags;
u32 gpe_en;
community = intel_get_community(pctrl, pin);
if (!community)
return -EINVAL;
raw_spin_lock_irqsave(&pctrl->lock, flags);
padno = pin_to_padno(community, pin);
gpp = padno / community->gpp_size;
gpp_offset = padno % community->gpp_size;
@ -821,6 +824,8 @@ static int intel_gpio_irq_wake(struct irq_data *d, unsigned int on)
gpe_en &= ~BIT(gpp_offset);
writel(gpe_en, community->regs + GPI_GPE_EN + gpp * 4);
raw_spin_unlock_irqrestore(&pctrl->lock, flags);
dev_dbg(pctrl->dev, "%sable wake for pin %u\n", on ? "en" : "dis", pin);
return 0;
}