gfs2: Don't clear GBF_FULL flags in rs_deltree

Removing a reservation doesn't make any actual space available, so don't clear
the GBF_FULL flags in that case.  Otherwise, we'll only spend more time
scanning the bitmaps unnecessarily.

Signed-off-by: Andreas Gruenbacher <agruenba@redhat.com>
This commit is contained in:
Andreas Gruenbacher 2020-10-06 15:16:16 +02:00
parent 2fdc2fa21b
commit a12c6fa1de

View file

@ -327,20 +327,6 @@ static bool gfs2_rbm_add(struct gfs2_rbm *rbm, u32 blocks)
}
}
static struct gfs2_bitmap *gfs2_block_to_bitmap(struct gfs2_rgrpd *rgd,
u64 block)
{
unsigned int delta = (sizeof(struct gfs2_rgrp) -
sizeof(struct gfs2_meta_header)) * GFS2_NBBY;
unsigned int rblock, bii;
if (!rgrp_contains_block(rgd, block))
return NULL;
rblock = block - rgd->rd_data0;
bii = (rblock + delta) / rgd->rd_sbd->sd_blocks_per_bitmap;
return rgd->rd_bits + bii;
}
/**
* gfs2_unaligned_extlen - Look for free blocks which are not byte aligned
* @rbm: Position to search (value/result)
@ -660,25 +646,16 @@ static void __rs_deltree(struct gfs2_blkreserv *rs)
RB_CLEAR_NODE(&rs->rs_node);
if (rs->rs_free) {
u64 last_block = rs->rs_start + rs->rs_free - 1;
struct gfs2_bitmap *start, *last;
/* return reserved blocks to the rgrp */
BUG_ON(rs->rs_rgd->rd_reserved < rs->rs_free);
rs->rs_rgd->rd_reserved -= rs->rs_free;
/* The rgrp extent failure point is likely not to increase;
it will only do so if the freed blocks are somehow
contiguous with a span of free blocks that follows. Still,
it will force the number to be recalculated later. */
rgd->rd_extfail_pt += rs->rs_free;
rs->rs_free = 0;
start = gfs2_block_to_bitmap(rgd, rs->rs_start);
last = gfs2_block_to_bitmap(rgd, last_block);
if (!start || !last)
return;
do
clear_bit(GBF_FULL, &start->bi_flags);
while (start++ != last);
}
}