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sched: no need to aggregate task_weight
We only need to know the task_weight of the busiest rq - nothing to do if there are no tasks there. Signed-off-by: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com> Cc: Mike Galbraith <efault@gmx.de> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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2 changed files with 2 additions and 16 deletions
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@ -433,12 +433,6 @@ struct cfs_rq {
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* The sum of all runqueue weights within this span.
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*/
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unsigned long rq_weight;
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/*
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* Weight contributed by tasks; this is the part we can
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* influence by moving tasks around.
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*/
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unsigned long task_weight;
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} aggregate;
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#endif
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#endif
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@ -1473,10 +1467,6 @@ static int task_hot(struct task_struct *p, u64 now, struct sched_domain *sd);
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* rq_weight:
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* Direct sum of all the cpu's their rq weight, e.g. A would get 3 while
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* B would get 2.
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*
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* task_weight:
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* Part of the rq_weight contributed by tasks; all groups except B would
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* get 1, B gets 2.
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*/
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static inline struct aggregate_struct *
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@ -1524,16 +1514,12 @@ static void
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aggregate_group_weight(struct task_group *tg, int cpu, struct sched_domain *sd)
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{
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unsigned long rq_weight = 0;
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unsigned long task_weight = 0;
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int i;
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for_each_cpu_mask(i, sd->span) {
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for_each_cpu_mask(i, sd->span)
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rq_weight += tg->cfs_rq[i]->load.weight;
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task_weight += tg->cfs_rq[i]->task_weight;
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}
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aggregate(tg, cpu)->rq_weight = rq_weight;
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aggregate(tg, cpu)->task_weight = task_weight;
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}
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/*
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@ -1427,7 +1427,7 @@ load_balance_fair(struct rq *this_rq, int this_cpu, struct rq *busiest,
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/*
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* empty group
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*/
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if (!aggregate(tg, this_cpu)->task_weight)
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if (!tg->cfs_rq[busiest_cpu]->task_weight)
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continue;
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rem_load = rem_load_move * aggregate(tg, this_cpu)->rq_weight;
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