mfd: Set da903x bits if new value is different from the old one

It does not make sense to write new value only when all the bit_mask
bits are zero.
We need to write new value if the bit mask fields of new value is
not equal to old value.

Signed-off-by: Axel Lin <axel.lin@gmail.com>
Signed-off-by: Samuel Ortiz <sameo@linux.intel.com>
This commit is contained in:
Axel Lin 2011-10-31 14:23:03 +08:00 committed by Samuel Ortiz
parent 890c98e374
commit af65e6cef4

View file

@ -182,7 +182,7 @@ int da903x_set_bits(struct device *dev, int reg, uint8_t bit_mask)
if (ret)
goto out;
if ((reg_val & bit_mask) == 0) {
if ((reg_val & bit_mask) != bit_mask) {
reg_val |= bit_mask;
ret = __da903x_write(chip->client, reg, reg_val);
}