io_uring: simplify io_req_link_next()

"if (nxt)" is always true, as it was checked in the while's condition.
io_wq_current_is_worker() is unnecessary, as non-async callers don't
pass nxt, so io_queue_async_work() will be called for them anyway.

Signed-off-by: Pavel Begunkov <asml.silence@gmail.com>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
This commit is contained in:
Pavel Begunkov 2019-11-21 23:21:02 +03:00 committed by Jens Axboe
parent 944e58bfed
commit b18fdf71e0

View file

@ -903,16 +903,7 @@ static void io_req_link_next(struct io_kiocb *req, struct io_kiocb **nxtptr)
nxt->flags |= REQ_F_LINK;
}
/*
* If we're in async work, we can continue processing the chain
* in this context instead of having to queue up new async work.
*/
if (nxt) {
if (io_wq_current_is_worker())
*nxtptr = nxt;
else
io_queue_async_work(nxt);
}
*nxtptr = nxt;
break;
}