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slow_work_thread() should do the exclusive wait
slow_work_thread() sleeps on slow_work_thread_wq without WQ_FLAG_EXCLUSIVE, this means that slow_work_enqueue()->__wake_up(nr_exclusive => 1) wakes up all kslowd threads. This is not what we want, so we change slow_work_thread() to use prepare_to_wait_exclusive() instead. Signed-off-by: Oleg Nesterov <oleg@redhat.com> Signed-off-by: David Howells <dhowells@redhat.com> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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1 changed files with 2 additions and 2 deletions
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@ -372,8 +372,8 @@ static int slow_work_thread(void *_data)
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vsmax *= atomic_read(&slow_work_thread_count);
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vsmax /= 100;
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prepare_to_wait(&slow_work_thread_wq, &wait,
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TASK_INTERRUPTIBLE);
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prepare_to_wait_exclusive(&slow_work_thread_wq, &wait,
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TASK_INTERRUPTIBLE);
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if (!freezing(current) &&
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!slow_work_threads_should_exit &&
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!slow_work_available(vsmax) &&
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