x86/32: Print control and debug registers for kerenel context

While for a user mode register dump it may be reasonable to skip
those (albeit x86-64 doesn't do so), for kernel mode dumps these
should be printed to make sure all information possibly
necessary for analysis is available.

Signed-off-by: Jan Beulich <jbeulich@suse.com>
Link: http://lkml.kernel.org/r/4F58889202000078000770E7@nat28.tlf.novell.com
Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
Jan Beulich 2012-03-08 09:23:14 +00:00 committed by Ingo Molnar
parent 0d2bf4899d
commit c7e23289a6

View file

@ -87,7 +87,7 @@ void show_registers(struct pt_regs *regs)
int i;
print_modules();
__show_regs(regs, 0);
__show_regs(regs, !user_mode_vm(regs));
printk(KERN_EMERG "Process %.*s (pid: %d, ti=%p task=%p task.ti=%p)\n",
TASK_COMM_LEN, current->comm, task_pid_nr(current),