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x86/32: Print control and debug registers for kerenel context
While for a user mode register dump it may be reasonable to skip those (albeit x86-64 doesn't do so), for kernel mode dumps these should be printed to make sure all information possibly necessary for analysis is available. Signed-off-by: Jan Beulich <jbeulich@suse.com> Link: http://lkml.kernel.org/r/4F58889202000078000770E7@nat28.tlf.novell.com Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -87,7 +87,7 @@ void show_registers(struct pt_regs *regs)
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int i;
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print_modules();
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__show_regs(regs, 0);
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__show_regs(regs, !user_mode_vm(regs));
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printk(KERN_EMERG "Process %.*s (pid: %d, ti=%p task=%p task.ti=%p)\n",
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TASK_COMM_LEN, current->comm, task_pid_nr(current),
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