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opp: Filter out OPPs based on availability of a required-OPP

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A required OPP may not be available, and thus, all OPPs which are using
this required OPP should be unavailable too.

Tested-by: Peter Geis <pgwipeout@gmail.com>
Tested-by: Nicolas Chauvet <kwizart@gmail.com>
Tested-by: Matt Merhar <mattmerhar@protonmail.com>
Signed-off-by: Dmitry Osipenko <digetx@gmail.com>
Signed-off-by: Viresh Kumar <viresh.kumar@linaro.org>
This commit is contained in:
Dmitry Osipenko 2021-01-18 03:55:14 +03:00 committed by Viresh Kumar
parent 32715be4fe
commit cf65948d62
1 changed files with 11 additions and 0 deletions
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11
drivers/opp/core.c
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@ -1522,6 +1522,7 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
struct opp_table *opp_table, bool rate_not_available)
{
struct list_head *head;
unsigned int i;
int ret;
mutex_lock(&opp_table->lock);
@ -1547,6 +1548,16 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
__func__, new_opp->rate);
}
for (i = 0; i < opp_table->required_opp_count; i++) {
if (new_opp->required_opps[i]->available)
continue;
new_opp->available = false;
dev_warn(dev, "%s: OPP not supported by required OPP %pOF (%lu)\n",
__func__, new_opp->required_opps[i]->np, new_opp->rate);
break;
}
return 0;
}