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io_uring: fix break condition for __io_uring_register() waiting

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Colin reports that there's unreachable code, since we only ever break
if ret == 0. This is correct, and is due to a reversed logic condition
in when to break or not.

Break out of the loop if we don't process any task work, in that case
we do want to return -EINTR.

Fixes: af9c1a44f8 ("io_uring: process task work in io_uring_register()")
Reported-by: Colin Ian King <colin.king@canonical.com>
Signed-off-by: Jens Axboe <axboe@kernel.dk>
This commit is contained in:
Jens Axboe 2020-10-08 19:09:46 -06:00
parent ca6484cd30
commit ed6930c920
1 changed files with 3 additions and 3 deletions
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6
fs/io_uring.c
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@ -9511,15 +9511,15 @@ static int __io_uring_register(struct io_ring_ctx *ctx, unsigned opcode,
ret = wait_for_completion_interruptible(&ctx->ref_comp);
if (!ret)
break;
if (io_run_task_work_sig() > 0)
continue;
ret = io_run_task_work_sig();
if (ret < 0)
break;
} while (1);
mutex_lock(&ctx->uring_lock);
if (ret) {
percpu_ref_resurrect(&ctx->refs);
ret = -EINTR;
goto out_quiesce;
}
}