nfp: calculate total port lanes for split

For port splitting we will need to know the total number of lanes
in a port.  Calculate that based on eth_table information.

Signed-off-by: Jakub Kicinski <jakub.kicinski@netronome.com>
Reviewed-by: Simon Horman <simon.horman@netronome.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Jakub Kicinski 2017-05-26 01:03:35 -07:00 committed by David S. Miller
parent 53e7a08f0d
commit f0b8119538
2 changed files with 9 additions and 5 deletions

View file

@ -96,6 +96,7 @@ enum nfp_eth_aneg {
* @override_changed: is media reconfig pending?
*
* @port_type: one of %PORT_* defines for ethtool
* @port_lanes: total number of lanes on the port (sum of lanes of all subports)
* @is_split: is interface part of a split port
*/
struct nfp_eth_table {
@ -127,6 +128,8 @@ struct nfp_eth_table {
/* Computed fields */
u8 port_type;
unsigned int port_lanes;
bool is_split;
} ports[0];
};

View file

@ -186,17 +186,19 @@ nfp_eth_port_translate(struct nfp_nsp *nsp, const union eth_table_entry *src,
}
static void
nfp_eth_mark_split_ports(struct nfp_cpp *cpp, struct nfp_eth_table *table)
nfp_eth_calc_port_geometry(struct nfp_cpp *cpp, struct nfp_eth_table *table)
{
unsigned int i, j;
for (i = 0; i < table->count; i++)
for (j = 0; j < table->count; j++) {
if (i == j)
continue;
if (table->ports[i].label_port !=
table->ports[j].label_port)
continue;
table->ports[i].port_lanes += table->ports[j].lanes;
if (i == j)
continue;
if (table->ports[i].label_subport ==
table->ports[j].label_subport)
nfp_warn(cpp,
@ -205,7 +207,6 @@ nfp_eth_mark_split_ports(struct nfp_cpp *cpp, struct nfp_eth_table *table)
table->ports[i].label_subport);
table->ports[i].is_split = true;
break;
}
}
@ -289,7 +290,7 @@ __nfp_eth_read_ports(struct nfp_cpp *cpp, struct nfp_nsp *nsp)
nfp_eth_port_translate(nsp, &entries[i], i,
&table->ports[j++]);
nfp_eth_mark_split_ports(cpp, table);
nfp_eth_calc_port_geometry(cpp, table);
for (i = 0; i < table->count; i++)
nfp_eth_calc_port_type(cpp, &table->ports[i]);