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pinctrl: don't put the reference to GPIO device in pinctrl_pins_show() 

The call to gpiod_to_gpio_device() does not increase the reference count
of the GPIO device struct so it must not be decreased. Remove the buggy
__free() decorator.

Fixes: 524fc108b8 ("pinctrl: stop using gpiod_to_chip()")
Reported-by: David Arcari <darcari@redhat.com>
Signed-off-by: Bartosz Golaszewski <bartosz.golaszewski@linaro.org>
Link: https://lore.kernel.org/r/20240223123214.288181-1-brgl@bgdev.pl
Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
This commit is contained in:
Bartosz Golaszewski 2024-02-23 13:32:14 +01:00 committed by Linus Walleij
parent cb4443f26b
commit f6443e0177
1 changed files with 1 additions and 1 deletions
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2
drivers/pinctrl/core.c
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@ -1644,7 +1644,7 @@ static int pinctrl_pins_show(struct seq_file *s, void *what)
const struct pinctrl_ops *ops = pctldev->desc->pctlops;
unsigned int i, pin;
#ifdef CONFIG_GPIOLIB
struct gpio_device *gdev __free(gpio_device_put) = NULL;
struct gpio_device *gdev = NULL;
struct pinctrl_gpio_range *range;
int gpio_num;
#endif