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kexec: prevent double free on image allocation failure

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If kimage_normal_alloc() fails to initialize an allocated kimage, it will
free the image but would still set 'rimage', as a result kexec_load will
try to free it again.

This would explode as part of the freeing process is accessing internal
members which point to uninitialized memory.

Signed-off-by: Sasha Levin <sasha.levin@oracle.com>
Cc: "Eric W. Biederman" <ebiederm@xmission.com>
Cc: Zhang Yanfei <zhangyanfei@cn.fujitsu.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Sasha Levin 2013-02-27 17:03:28 -08:00 committed by Linus Torvalds
parent 0d0bf66741
commit fe88f2ee33
1 changed files with 0 additions and 2 deletions
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2
kernel/kexec.c
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@ -242,8 +242,6 @@ static int kimage_normal_alloc(struct kimage **rimage, unsigned long entry,
if (result)
goto out;
*rimage = image;
/*
* Find a location for the control code buffer, and add it
* the vector of segments so that it's pages will also be