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The signal return code is responsible for taking an XSAVE buffer present in user memory and loading it into the hardware registers. This operation only affects user XSAVE state and never affects supervisor state. The fast path through this code simply points XRSTOR directly at the user buffer. However, since user memory is not guaranteed to be always mapped, this XRSTOR can fail. If it fails, the signal return code falls back to a slow path which can tolerate page faults. That slow path copies the xfeatures one by one out of the user buffer into the task's fpu state area. However, by being in a context where it can handle page faults, the code can also schedule. The lazy-fpu-load code would think it has an up-to-date fpstate and would fail to save the supervisor state when scheduling the task out. When scheduling back in, it would likely restore stale supervisor state. To fix that, preserve supervisor state before the slow path. Modify copy_user_to_fpregs_zeroing() so that if it fails, fpregs are not zeroed, and there is no need for fpregs_deactivate() and supervisor states are preserved. Move set_thread_flag(TIF_NEED_FPU_LOAD) to the slow path. Without doing this, the fast path also needs supervisor states to be saved first. Signed-off-by: Yu-cheng Yu <yu-cheng.yu@intel.com> Signed-off-by: Borislav Petkov <bp@suse.de> Link: https://lkml.kernel.org/r/20200512145444.15483-10-yu-cheng.yu@intel.com |
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