2015-03-19 21:47:43 +00:00
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package merkle
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2015-03-25 21:28:17 +00:00
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import (
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2015-08-16 23:12:32 +00:00
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"fmt"
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"hash"
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2015-08-16 23:12:32 +00:00
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"os"
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2015-03-30 19:02:53 +00:00
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"runtime"
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2015-03-25 21:28:17 +00:00
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)
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2015-03-19 21:47:43 +00:00
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// NewHash provides a hash.Hash to generate a merkle.Tree checksum, given a
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// HashMaker for the checksums of the blocks written and the blockSize of each
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// block per node in the tree.
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2015-03-30 19:19:46 +00:00
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func NewHash(hm HashMaker, merkleBlockLength int) HashTreeer {
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2015-03-31 14:55:25 +00:00
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return newMerkleHash(hm, merkleBlockLength)
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}
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func newMerkleHash(hm HashMaker, merkleBlockLength int) *merkleHash {
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mh := new(merkleHash)
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mh.blockSize = merkleBlockLength
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mh.hm = hm
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mh.tree = &Tree{Nodes: []*Node{}, BlockLength: merkleBlockLength}
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mh.lastBlock = make([]byte, merkleBlockLength)
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return mh
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}
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2015-03-30 19:19:46 +00:00
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// Treeer (Tree-er) provides access to the Merkle tree internals
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type Treeer interface {
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Nodes() []*Node
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Root() *Node
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}
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// HashTreeer can be used as a hash.Hash but also provide access to the Merkle
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// tree internals
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type HashTreeer interface {
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hash.Hash
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Treeer
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}
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2015-03-19 21:47:43 +00:00
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// TODO make a similar hash.Hash, that accepts an argument of a merkle.Tree,
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// that will validate nodes as the new bytes are written. If a new written
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// block fails checksum, then return an error on the io.Writer
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type merkleHash struct {
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blockSize int
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tree *Tree
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hm HashMaker
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lastBlock []byte // as needed, for Sum()
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lastBlockLen int
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partialLastNode bool // true when Sum() has appended a Node for a partial block
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}
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func (mh *merkleHash) Reset() {
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mh.tree = &Tree{Nodes: []*Node{}, BlockLength: mh.blockSize}
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mh.lastBlockLen = 0
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mh.partialLastNode = false
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}
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func (mh merkleHash) Nodes() []*Node {
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return mh.tree.Nodes
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}
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func (mh merkleHash) Root() *Node {
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return mh.tree.Root()
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}
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2015-03-19 21:47:43 +00:00
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// XXX this will be tricky, as the last block can be less than the BlockSize.
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// if they get the sum, it will be mh.tree.Root().Checksum() at that point.
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//
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// But if they continue writing, it would mean a continuation of the bytes in
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// the last block. So popping the last node, and having a buffer for the bytes
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// in that last partial block.
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//
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// if that last block was complete, then no worries. start the next node.
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func (mh *merkleHash) Sum(b []byte) []byte {
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var (
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curBlock = []byte{}
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offset int
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)
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if mh.partialLastNode {
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// if this is true, then we need to pop the last node
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mh.tree.Nodes = mh.tree.Nodes[:len(mh.tree.Nodes)-1]
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mh.partialLastNode = false
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}
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if mh.lastBlockLen > 0 {
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curBlock = append(curBlock[:], mh.lastBlock[:mh.lastBlockLen]...)
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mh.lastBlockLen = 0
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}
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if b != nil && len(b) > 0 {
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curBlock = append(curBlock, b...)
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}
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2015-03-31 14:55:25 +00:00
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// incase we're at a new or reset state
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if len(mh.tree.Nodes) == 0 && len(curBlock) == 0 {
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return nil
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}
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2015-03-30 19:02:53 +00:00
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for i := 0; i < len(curBlock)/mh.blockSize; i++ {
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n, err := NewNodeHashBlock(mh.hm, curBlock[offset:(offset+mh.blockSize)])
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if err != nil {
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// XXX i hate to swallow an error here, but the `Sum() []byte` signature
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// :-\
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sBuf := make([]byte, 1024)
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runtime.Stack(sBuf, false)
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fmt.Fprintf(os.Stderr, "[ERROR]: %s %q", err, string(sBuf))
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return nil
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}
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mh.tree.Nodes = append(mh.tree.Nodes, n)
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offset = offset + mh.blockSize
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}
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// If there is remainder, we'll need to make a partial node and stash it
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if m := (len(curBlock) % mh.blockSize); m != 0 {
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mh.lastBlockLen = copy(mh.lastBlock, curBlock[offset:])
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n, err := NewNodeHashBlock(mh.hm, curBlock[offset:])
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if err != nil {
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sBuf := make([]byte, 1024)
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runtime.Stack(sBuf, false)
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fmt.Fprintf(os.Stderr, "[ERROR]: %s %q", err, string(sBuf))
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return nil
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}
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mh.tree.Nodes = append(mh.tree.Nodes, n)
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mh.partialLastNode = true
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}
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2015-03-25 21:28:17 +00:00
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sum, err := mh.tree.Root().Checksum()
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if err != nil {
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// XXX i hate to swallow an error here, but the `Sum() []byte` signature
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// :-\
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sBuf := make([]byte, 1024)
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runtime.Stack(sBuf, false)
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fmt.Fprintf(os.Stderr, "[ERROR]: %s %q", err, string(sBuf))
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return nil
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}
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return sum
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}
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func (mh *merkleHash) Write(b []byte) (int, error) {
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// basically we need to:
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// * include prior partial lastBlock, if any
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// * chunk these writes into blockSize
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// * create Node of the sum
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// * add the Node to the tree
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// * stash remainder in the mh.lastBlock
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var (
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curBlock = make([]byte, mh.blockSize)
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numBytes int
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numWritten int
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offset int
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)
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if mh.lastBlock != nil && mh.lastBlockLen > 0 {
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if (mh.lastBlockLen + len(b)) < mh.blockSize {
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mh.lastBlockLen += copy(mh.lastBlock[mh.lastBlockLen:], b[:])
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return len(b), nil
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}
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2015-03-26 22:24:34 +00:00
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// XXX off by one?
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numBytes = copy(curBlock[:], mh.lastBlock[:mh.lastBlockLen])
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// not adding to numWritten, since these blocks were accounted for in a
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// prior Write()
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2015-03-26 20:46:02 +00:00
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// then we'll chunk the front of the incoming bytes
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end := mh.blockSize - numBytes
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if end > len(b) {
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end = len(b)
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}
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offset = copy(curBlock[numBytes:], b[:end])
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n, err := NewNodeHashBlock(mh.hm, curBlock)
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if err != nil {
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// XXX might need to stash again the prior lastBlock and first little chunk
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return numWritten, err
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}
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mh.tree.Nodes = append(mh.tree.Nodes, n)
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numWritten += offset
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}
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numBytes = (len(b) - offset)
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for i := 0; i < numBytes/mh.blockSize; i++ {
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//fmt.Printf("%s", b[offset:offset+mh.blockSize])
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numWritten += copy(curBlock, b[offset:offset+mh.blockSize])
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n, err := NewNodeHashBlock(mh.hm, curBlock)
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if err != nil {
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// XXX might need to stash again the prior lastBlock and first little chunk
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return numWritten, err
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}
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mh.tree.Nodes = append(mh.tree.Nodes, n)
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offset = offset + mh.blockSize
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}
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2015-03-26 22:24:34 +00:00
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mh.lastBlockLen = numBytes % mh.blockSize
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// XXX off by one?
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numWritten += copy(mh.lastBlock[:], b[(len(b)-mh.lastBlockLen):])
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2015-03-25 21:28:17 +00:00
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return numWritten, nil
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2015-03-19 21:47:43 +00:00
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}
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2015-03-25 21:28:17 +00:00
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// likely not the best to pass this through and not use our own node block
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// size, but let's revisit this.
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2015-03-19 21:47:43 +00:00
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func (mh *merkleHash) BlockSize() int { return mh.hm().BlockSize() }
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func (mh *merkleHash) Size() int { return mh.hm().Size() }
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