201 lines
7.6 KiB
Java
201 lines
7.6 KiB
Java
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/*
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The contents of this file are subject to the THDL Open Community License
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Version 1.0 (the "License"); you may not use this file except in compliance
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with the License. You may obtain a copy of the License on the THDL web site
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(http://www.thdl.org/).
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Software distributed under the License is distributed on an "AS IS" basis,
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WITHOUT WARRANTY OF ANY KIND, either express or implied. See the
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License for the specific terms governing rights and limitations under the
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License.
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The Initial Developer of this software is the Tibetan and Himalayan Digital
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Library (THDL). Portions created by the THDL are Copyright 2003 THDL.
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All Rights Reserved.
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Contributor(s): ______________________________________.
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*/
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package org.thdl.tib.text.ttt;
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import java.util.ArrayList;
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/** A list of non-empty list of {@link #TStackListList
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* TStackListLists} representing all the ways you could break up a
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* tsheg bar of ACIP into stacks (i.e., grapheme clusters).
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*
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* @author David Chandler */
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class TParseTree {
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/** a fast, non-thread-safe, random-access list implementation: */
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private ArrayList al = new ArrayList();
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/** Creates an empty list. */
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public TParseTree() { }
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/** Returns the ith pair in this list. */
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public TStackListList get(int i) { return (TStackListList)al.get(i); }
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/** Adds p to the end of this list. */
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public void add(TStackListList p)
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throws IllegalArgumentException
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{
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if (p.isEmpty())
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throw new IllegalArgumentException("p is empty");
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al.add(p);
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}
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/** Returns the number of TStackListLists in this list. See
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* also {@link #numberOfParses()}, which gives a different
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* interpretation of the size of this tree. */
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public int size() { return al.size(); }
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/** Returns the number of different parses one could make from
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* this parse tree. Returns zero if this list is empty. */
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public int numberOfParses() {
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if (al.isEmpty()) return 0;
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int k = 1;
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int sz = size();
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for (int i = 0; i < sz; i++) {
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k *= get(i).size();
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}
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return k;
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}
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/** Returns the number of {@link #TPair pairs} that are in a
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* parse of this tree. */
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public int numberOfPairs() {
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if (al.isEmpty()) return 0;
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int k = 1;
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int sz = size();
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for (int i = 0; i < sz; i++) {
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// get(i).get(0) is the same size as get(i).get(1),
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// get(i).get(2), ...
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k += get(i).get(0).size();
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}
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return k;
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}
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/** Returns an iterator that will iterate over the {@link
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* #numberOfParses} available. */
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public ParseIterator getParseIterator() {
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return new ParseIterator(al);
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}
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/** Returns a list containing the legal parses of this parse tree.
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* By "legal", we mean a sequence of stacks that is
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* legal by the rules of Tibetan tsheg bar syntax (sometimes
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* called spelling). This will return the {G-YA} parse of {GYA}
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* as well as the {GYA} parse, so watch yourself. */
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public TStackListList getLegalParses() {
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TStackListList sll = new TStackListList(2); // save memory
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ParseIterator pi = getParseIterator();
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while (pi.hasNext()) {
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TStackList sl = pi.next();
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if (sl.isLegalTshegBar().isLegal) {
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sll.add(sl);
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}
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}
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return sll;
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}
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/** Returns a list containing the parses of this parse tree that
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* are not clearly illegal. */
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public TStackListList getNonIllegalParses() {
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TStackListList sll = new TStackListList(2); // save memory
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ParseIterator pi = getParseIterator();
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while (pi.hasNext()) {
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TStackList sl = pi.next();
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if (!sl.isClearlyIllegal()) {
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sll.add(sl);
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}
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}
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return sll;
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}
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/** Returns the best parse, if there is a unique parse that is
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* clearly preferred to other parses. Basically, if there's a
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* unique legal parse, you get it. If there's not, but there is
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* a unique non-illegal parse, you get it. If there's not a
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* unique answer, null is returned. */
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// {TZANDRA} is not solved by this, DLC NOW. Solve PADMA PROBLEM!
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// DLC by using this we can get rid of single-sanskrit-gc, eh?
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public TStackList getBestParse() {
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TStackListList up = getUniqueParse();
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if (up.size() == 1)
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return up.get(0);
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else if (up.size() == 2) {
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}
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up = getNonIllegalParses();
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int sz = up.size();
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if (up.size() == 1) {
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return up.get(0);
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}
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return null;
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}
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/** Returns a list containing the unique legal parse of this parse
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* tree if there is a unique legal parse. Note that {SRAS} has a
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* unique legal parse, though {SRS} has two equally good parses;
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* i.e., note that the {A} vowel is treated specially here
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* (unlike in {@link #getLegalParses()}). Returns an empty list
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* if there are no legal parses. Returns a list containing all
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* legal parses if there two or more equally good parses. By
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* "legal", we mean a sequence of stacks that is legal
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* by the rules of Tibetan tsheg bar syntax (sometimes called
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* spelling). */
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public TStackListList getUniqueParse() {
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TStackListList allLegalParses = new TStackListList(2); // save memory
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TStackListList legalParsesWithVowelOnRoot = new TStackListList(1);
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ParseIterator pi = getParseIterator();
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while (pi.hasNext()) {
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TStackList sl = pi.next();
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BoolPair bpa = sl.isLegalTshegBar();
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if (bpa.isLegal) {
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if (bpa.isLegalAndHasAVowelOnRoot)
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legalParsesWithVowelOnRoot.add(sl);
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allLegalParses.add(sl);
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}
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}
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if (legalParsesWithVowelOnRoot.size() == 1)
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return legalParsesWithVowelOnRoot;
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else {
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if (legalParsesWithVowelOnRoot.size() == 2) {
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// DLC is this even valid?
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if (legalParsesWithVowelOnRoot.get(0).size() != 1 + legalParsesWithVowelOnRoot.get(1).size())
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throw new Error("Something other than the G-YA vs. GYA case appeared. Sorry for your trouble! " + legalParsesWithVowelOnRoot.get(0) + " ;; " + legalParsesWithVowelOnRoot.get(1));
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return new TStackListList(legalParsesWithVowelOnRoot.get(1));
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}
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if (allLegalParses.size() == 2) {
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// DLC is this even valid?
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if (allLegalParses.get(0).size() != 1 + allLegalParses.get(1).size())
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throw new Error("Something other than the G-YA vs. GYA case appeared. Sorry for your trouble! " + allLegalParses.get(0) + " ;; " + allLegalParses.get(1));
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return new TStackListList(allLegalParses.get(1));
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}
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return allLegalParses;
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}
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}
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/** Returns a human-readable representation. */
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public String toString() {
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return al.toString();
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}
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/** Returns true if and only if either x is an TParseTree
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* object representing the same TPairLists in the same order
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* or x is a String that is equals to the result of {@link
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* #toString()}. */
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public boolean equals(Object x) {
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if (x instanceof TParseTree) {
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return al.equals(((TParseTree)x).al);
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} else if (x instanceof String) {
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return toString().equals(x);
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}
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return false;
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}
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/** Returns a hashCode appropriate for use with our {@link
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* #equals(Object)} method. */
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public int hashCode() { return al.hashCode(); }
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}
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