315 lines
11 KiB
Java
315 lines
11 KiB
Java
/*
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* ====================================================================
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*
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* The Apache Software License, Version 1.1
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*
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* Copyright (c) 1999-2003 The Apache Software Foundation.
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* All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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*
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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*
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in
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* the documentation and/or other materials provided with the
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* distribution.
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*
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* 3. The end-user documentation included with the redistribution, if
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* any, must include the following acknowlegement:
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* "This product includes software developed by the
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* Apache Software Foundation (http://www.apache.org/)."
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* Alternately, this acknowlegement may appear in the software itself,
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* if and wherever such third-party acknowlegements normally appear.
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*
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* 4. The names "The Jakarta Project", "Commons", and "Apache Software
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* Foundation" must not be used to endorse or promote products derived
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* from this software without prior written permission. For written
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* permission, please contact apache@apache.org.
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*
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* 5. Products derived from this software may not be called "Apache"
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* nor may "Apache" appear in their names without prior written
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* permission of the Apache Group.
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*
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* THIS SOFTWARE IS PROVIDED ``AS IS'' AND ANY EXPRESSED OR IMPLIED
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* WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
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* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
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* DISCLAIMED. IN NO EVENT SHALL THE APACHE SOFTWARE FOUNDATION OR
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* ITS CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
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* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
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* LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF
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* USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
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* ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,
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* OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT
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* OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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* ====================================================================
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*
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* This software consists of voluntary contributions made by many
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* individuals on behalf of the Apache Software Foundation. For more
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* information on the Apache Software Foundation, please see
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* <http://www.apache.org/>.
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*
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*/
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package org.apache.commons.jrcs.diff;
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import java.util.*;
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/**
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* Implements a simple differencing algortithm.<p>
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*
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* @date $Date: 2003/07/14 12:22:29 $
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* @version $Revision: 1.1 $
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* @author <a href="mailto:juanco@suigeneris.org">Juanco Anez</a>
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*
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* <p><b>Overview of Algorithm</b></p>
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*
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* <p><i>by <a
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* href='http://www.topmeadow.net/bwm'> bwm</a>
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* </p>
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*
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* <p>The algorithm is optimised for situations where the input sequences
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* have few repeated objects. If it is given input with many repeated
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* objects it will report sub-optimal changes. However, given appropriate
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* input, it is fast, and linear in memory usage.</p>
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*
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* <p>The algorithm consists of the following steps:</p>
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* <ul>
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* <li>compute an equivalence set for the input data</li>
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* <li>translate each element of the orginal
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* and revised input sequences to a member of the equivalence set
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* </li>
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* <li>match the the input sequences to determine the deltas, i.e.
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* the differences between the original and revised sequences.</li>
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* </ul>
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*
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* <p>The first step is to compute a an equivalence set for the input data.
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* The equivalence set is computed from objects that are in the original
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* input sequence</p>
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* <pre>
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* eq(x) = the index of the first occurence of x in the original sequence.
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* </pre>
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*
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* <p>With this equivalence function, the algorithm can compare integers rather
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* than strings, which is considerably more efficient.</p>
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*
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* <p>The second step is to compute the datastructure on which the
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* algorithm will operate. Having computed the equivalence function
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* in the previous step, we can compute two arrays where
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* indx[i] = eqs(orig[i]) and jndx[i] = eqs(rev[i]). The algorithm can
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* now operate on indx and jndx instead of orig and rev. Thus, comparisons
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* are then on O(int == int) instead of O(Object.equals(Object)).
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* </p>
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*
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* <p>The algorithm now matches indx and jndx. Whilst indx[i] == jndx[i]
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* it skips matching objects in the sequence. In seeking to match objects
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* in the input sequence it assumes that each object is likely to be unique.
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* It uses the known characteristics of the unique equivalence function. It can
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* tell from the eq value if this object appeared in the other sequence
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* at all. If it did not, there is no point in searching for a match.</p>
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*
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* <p>Recall that the eq function value is the index earliest occurrence in
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* the orig sequence. This information is used to search efficiently for
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* the next match. The algorithm is perfect when all input objects are
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* unique, but degrades when input objects are not unique. When input
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* objects are not unique an optimal match may not be found, but a
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* correct match will be.</p>
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*
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* <p>Having identified common matching objects in the orig and revised
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* sequences, the differences between them are easily computed.
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* </p>
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*
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* @see Delta
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* @see Revision
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* Modifications:
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*
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* 27/Apr/2003 bwm
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* Added some comments whilst trying to figure out the algorithm
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*
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* 03 May 2003 bwm
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* Created this implementation class by refactoring it out of the Diff
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* class to enable plug in difference algorithms
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*
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*/
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public class SimpleDiff
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implements DiffAlgorithm
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{
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static final int NOT_FOUND_i = -2;
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static final int NOT_FOUND_j = -1;
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static final int EOS = Integer.MAX_VALUE;
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public SimpleDiff()
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{
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}
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protected int scan(int[] ndx, int i, int target)
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{
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while (ndx[i] < target)
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{
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i++;
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}
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return i;
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}
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/**
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* Compute the difference between original and revised sequences.
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*
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* @param orig The original sequence.
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* @param rev The revised sequence to be compared with the original.
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* @return A Revision object describing the differences.
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* @throws DifferenciationFailedException if the diff could not be computed.
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*/
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public Revision diff(Object[] orig, Object[] rev)
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throws DifferentiationFailedException
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{
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// create map eqs, such that for each item in both orig and rev
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// eqs(item) = firstOccurrence(item, orig);
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Map eqs = buildEqSet(orig, rev);
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// create an array such that
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// indx[i] = NOT_FOUND_i if orig[i] is not in rev
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// indx[i] = firstOccurrence(orig[i], orig)
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int[] indx = buildIndex(eqs, orig, NOT_FOUND_i);
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// create an array such that
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// jndx[j] = NOT_FOUND_j if orig[j] is not in rev
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// jndx[j] = firstOccurrence(rev[j], orig)
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int[] jndx = buildIndex(eqs, rev, NOT_FOUND_j);
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// what in effect has been done is to build a unique hash
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// for each item that is in both orig and rev
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// and to label each item in orig and new with that hash value
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// or a marker that the item is not common to both.
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eqs = null; // let gc know we're done with this
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Revision deltas = new Revision(); //!!! new Revision()
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int i = 0;
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int j = 0;
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// skip matching
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// skip leading items that are equal
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// could be written
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// for (i=0; indx[i] != EOS && indx[i] == jndx[i]; i++);
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// j = i;
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for (; indx[i] != EOS && indx[i] == jndx[j]; i++, j++)
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{
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/* void */
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}
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while (indx[i] != jndx[j])
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{ // only equal if both == EOS
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// they are different
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int ia = i;
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int ja = j;
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// size of this delta
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do
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{
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// look down rev for a match
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// stop at a match
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// or if the FO(rev[j]) > FO(orig[i])
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// or at the end
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while (jndx[j] < 0 || jndx[j] < indx[i])
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{
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j++;
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}
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// look down orig for a match
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// stop at a match
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// or if the FO(orig[i]) > FO(rev[j])
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// or at the end
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while (indx[i] < 0 || indx[i] < jndx[j])
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{
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i++;
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}
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// this doesn't do a compare each line with each other line
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// so it won't find all matching lines
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}
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while (indx[i] != jndx[j]);
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// on exit we have a match
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// they are equal, reverse any exedent matches
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// it is possible to overshoot, so count back matching items
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while (i > ia && j > ja && indx[i - 1] == jndx[j - 1])
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{
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--i;
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--j;
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}
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deltas.addDelta(Delta.newDelta(new Chunk(orig, ia, i - ia),
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new Chunk(rev, ja, j - ja)));
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// skip matching
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for (; indx[i] != EOS && indx[i] == jndx[j]; i++, j++)
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{
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/* void */
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}
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}
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return deltas;
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}
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/**
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* create a <code>Map</code> from each common item in orig and rev
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* to the index of its first occurrence in orig
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*
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* @param orig the original sequence of items
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* @param rev the revised sequence of items
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*/
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protected Map buildEqSet(Object[] orig, Object[] rev)
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{
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// construct a set of the objects that orig and rev have in common
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// first construct a set containing all the elements in orig
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Set items = new HashSet(Arrays.asList(orig));
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// then remove all those not in rev
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items.retainAll(Arrays.asList(rev));
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Map eqs = new HashMap();
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for (int i = 0; i < orig.length; i++)
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{
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// if its a common item and hasn't been found before
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if (items.contains(orig[i]))
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{
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// add it to the map
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eqs.put(orig[i], new Integer(i));
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// and make sure its not considered again
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items.remove(orig[i]);
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}
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}
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return eqs;
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}
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/**
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* build a an array such each a[i] = eqs([i]) or NF if eqs([i]) undefined
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*
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* @param eqs a mapping from Object to Integer
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* @param seq a sequence of objects
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* @param NF the not found marker
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*/
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protected int[] buildIndex(Map eqs, Object[] seq, int NF)
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{
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int[] result = new int[seq.length + 1];
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for (int i = 0; i < seq.length; i++)
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{
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Integer value = (Integer) eqs.get(seq[i]);
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if (value == null || value.intValue() < 0)
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{
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result[i] = NF;
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}
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else
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{
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result[i] = value.intValue();
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}
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}
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result[seq.length] = EOS;
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return result;
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}
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}
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