cri-o/vendor/k8s.io/kubernetes/pkg/volume/glusterfs/glusterfs_minmax.go
Mrunal Patel 8e5b17cf13 Switch to github.com/golang/dep for vendoring
Signed-off-by: Mrunal Patel <mrunalp@gmail.com>
2017-01-31 16:45:59 -08:00

177 lines
3.3 KiB
Go

/*
Copyright 2016 The Kubernetes Authors.
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
*/
//
// This implementation is space-efficient for a sparse
// allocation over a big range. Could be optimized
// for high absolute allocation number with a bitmap.
//
package glusterfs
import (
"errors"
"sync"
)
var (
ErrNotFound = errors.New("number not allocated")
ErrConflict = errors.New("number already allocated")
ErrInvalidRange = errors.New("invalid range")
ErrOutOfRange = errors.New("out of range")
ErrRangeFull = errors.New("range full")
ErrInternal = errors.New("internal error")
)
type MinMaxAllocator struct {
lock sync.Mutex
min int
max int
free int
used map[int]bool
}
var _ Rangeable = &MinMaxAllocator{}
// Rangeable is an Interface that can adjust its min/max range.
// Rangeable should be threadsafe
type Rangeable interface {
Allocate(int) (bool, error)
AllocateNext() (int, bool, error)
Release(int) error
Has(int) bool
Free() int
SetRange(min, max int) error
}
func NewMinMaxAllocator(min, max int) (*MinMaxAllocator, error) {
if min > max {
return nil, ErrInvalidRange
}
return &MinMaxAllocator{
min: min,
max: max,
free: 1 + max - min,
used: map[int]bool{},
}, nil
}
func (a *MinMaxAllocator) SetRange(min, max int) error {
if min > max {
return ErrInvalidRange
}
a.lock.Lock()
defer a.lock.Unlock()
// Check if we need to change
if a.min == min && a.max == max {
return nil
}
a.min = min
a.max = max
// Recompute how many free we have in the range
num_used := 0
for i := range a.used {
if a.inRange(i) {
num_used++
}
}
a.free = 1 + max - min - num_used
return nil
}
func (a *MinMaxAllocator) Allocate(i int) (bool, error) {
a.lock.Lock()
defer a.lock.Unlock()
if !a.inRange(i) {
return false, ErrOutOfRange
}
if a.has(i) {
return false, ErrConflict
}
a.used[i] = true
a.free--
return true, nil
}
func (a *MinMaxAllocator) AllocateNext() (int, bool, error) {
a.lock.Lock()
defer a.lock.Unlock()
// Fast check if we're out of items
if a.free <= 0 {
return 0, false, ErrRangeFull
}
// Scan from the minimum until we find a free item
for i := a.min; i <= a.max; i++ {
if !a.has(i) {
a.used[i] = true
a.free--
return i, true, nil
}
}
// no free item found, but a.free != 0
return 0, false, ErrInternal
}
func (a *MinMaxAllocator) Release(i int) error {
a.lock.Lock()
defer a.lock.Unlock()
if !a.has(i) {
return nil
}
delete(a.used, i)
if a.inRange(i) {
a.free++
}
return nil
}
func (a *MinMaxAllocator) has(i int) bool {
_, ok := a.used[i]
return ok
}
func (a *MinMaxAllocator) Has(i int) bool {
a.lock.Lock()
defer a.lock.Unlock()
return a.has(i)
}
func (a *MinMaxAllocator) Free() int {
a.lock.Lock()
defer a.lock.Unlock()
return a.free
}
func (a *MinMaxAllocator) inRange(i int) bool {
return a.min <= i && i <= a.max
}